数据分析 005-pandas（三）聚合和分组
导入所需的库
import numpy as np |
函数应用和映射
函数映射
测试数据
df = pd.DataFrame(np.random.randn(4 ,3), columns=list('bde'), index=['Shenzhen', 'Beijing', 'Changsha', 'Shanghai']) |
apply()
用于对 DataFrame 中的数据进行按行或者按列操作
默认是 0 轴方向(也就是按列)
f = lambda x:x.max() - x.min() |
按 行 进行操作, 只需要家参数 axis
print(df.apply(f, axis=1)) |
使用内置平方根函数 sqrt()
df = pd.DataFrame([[4, 9]]*3, columns=[‘A’, ‘B’])
print(df)
‘’’
A B
0 4 9
1 4 9
2 4 9
‘’’
print(df.apply(np.sqrt))
‘’’
A B
0 2.0 3.0
1 2.0 3.0
2 2.0 3.0
‘’’
生活案例-计算税额
data = {
‘商品名称’: [‘商品A’, ‘商品B’, ‘商品C’, ‘商品D’],
‘销售价格’: [20.0, 15.0, 30.0, 25.0]
}
df = pd.DataFrame(data)
print(df)
‘’’
商品名称 销售价格
0 商品A 20.0
1 商品B 15.0
2 商品C 30.0
3 商品D 25.0
‘’’
df[‘销售税额’] = df[‘销售价格’].apply(lambda x:x*0.1)
print(df)
‘’’
商品名称 销售价格 销售税额
0 商品A 20.0 2.0
1 商品B 15.0 1.5
2 商品C 30.0 3.0
3 商品D 25.0 2.5
‘’’
相对于简单的运算也可以使用下面的计算方式
df[‘销售税额2’] = df[‘销售价格’]*0.1
print(df)
‘’’
商品名称 销售价格 销售税额 销售税额2
0 商品A 20.0 2.0 2.0
1 商品B 15.0 1.5 1.5
2 商品C 30.0 3.0 3.0
3 商品D 25.0 2.5 2.5
‘’’
def func(x):
return pd.Series([x.min(), x.max()], index=[‘min’, ‘max’])
print(df.apply(func))
‘’’
商品名称 销售价格 销售税额 销售税额2
min 商品A 15.0 1.5 1.5
max 商品D 30.0 3.0 3.0
‘’’
map()
用于对 Series 中的每一个数据操作，它可以是函数，也可以是字典
s = pd.Series([‘apple’, ‘banana’, ‘carrot’, ‘apple’, ‘banana’, ‘carrot’])
price = {‘apple’: 5.0, ‘banana’: 2.5, ‘carrot’: 1.2}
将商品和价格进行映射
map_s = s.map(price)
print(map_s)
‘’’
0 5.0
1 2.5
2 1.2
3 5.0
4 2.5
5 1.2
dtype: float64
‘’’
applymap()
用于对 DataFrame 的每一个元素操作
获取唯一索引
df.index.is_unique
判断是否是唯一值
df.index_unique()
获取唯一值
带有重复标签的轴索引
df = pd.Series(range(5), index=[‘a’, ‘a’, ‘b’, ‘b’, ‘c’])
print(df)
‘’’
dtype: float64
a 0
a 1
b 2
b 3
c 4
dtype: int64
‘’’
print(df.index.unique())
‘’’
Index([‘a’, ‘b’, ‘c’], dtype=’object’)
‘’’
统计方法及函数
data = {
‘姓名’: [‘Lucy’, ‘Lily’, ‘Tom’, ‘Jack’],
‘数学’: [85, 92, 78, 65],
‘英语’: [76, 88, 92, 71],
‘历史’: [90, 82, 68, 56]
}
df = pd.DataFrame(data)
print(df)
‘’’
姓名 数学 英语 历史
0 Lucy 85 76 90
1 Lily 92 88 82
2 Tom 78 92 68
3 Jack 65 71 56
‘’’
设置姓名这一列为索引
df = df.set_index(‘姓名’)
print(df)
‘’’
数学 英语 历史
姓名
Lucy 85 76 90
Lily 92 88 82
Tom 78 92 68
Jack 65 71 56
‘’’
求平均值
print(df.mean())
‘’’
数学 80.00
英语 81.75
历史 74.00
dtype: float64
‘’’
求每个学生的平均成绩
print(df.mean(axis=1))
‘’’
姓名
Lucy 83.666667
Lily 87.333333
Tom 79.333333
Jack 64.000000
dtype: float64
‘’’
求每科成绩最高分是谁？
print(df.idxmax()) # idxmax() 获取的是最高值及对应的索引
‘’’
数学 Lily
英语 Tom
历史 Lucy
dtype: object
‘’’
求每科成绩最低分是谁？
print(df.idxmin())
‘’’
数学 Jack
英语 Jack
历史 Jack
dtype: object
‘’’
累计函数
统计方法
数据处理
df1 = pd.DataFrame([[1, 2, 3], [NaN, 5, NaN], [NaN, 9, 8], [NaN, NaN, NaN]])
print(df1)
‘’’
0 1 2
0 1.0 2.0 3.0
1 NaN 5.0 NaN
2 NaN 9.0 8.0
3 NaN NaN NaN
‘’’
滤除空值： dropna()
作用于 Series 和 DataFrame
print(df1.dropna()) # 只要有空值就会删除（也称 暴力删除）,相当于加了参数 how=’any’
‘’’
0 1 2
0 1.0 2.0 3.0
‘’’
滤除全部为空值的行
print(df1.dropna(how=’all’)) # 只删除全部为空值的行
‘’’
0 1 2
0 1.0 2.0 3.0
1 NaN 5.0 NaN
2 NaN 9.0 8.0
‘’’
滤除全部为空值的列
print(df1.dropna(how=’all’,axis=1)) # 只删除全部为空值的列
‘’’
0 1 2
0 1.0 2.0 3.0
1 NaN 5.0 NaN
2 NaN 9.0 8.0
3 NaN NaN NaN
‘’’
阈值: thresh = n ，表示保留至少 n 个非空值数据的行
print(df.dropna(thresh=1)) # 保留每行至少有 1 个非空值数据的行
填充空值：fillna()
常数填充；均值填充；插值填充
print(df1.fillna(0))
‘’’
0 1 2
0 1.0 2.0 3.0
1 0.0 5.0 0.0
2 0.0 9.0 8.0
3 0.0 0.0 0.0
‘’’
每列填充不相同的值（将 0 列中的空值填充为10 ，1 列中的空值填充为20 ，2 列中的空值填充为30）
print(df1.fillna({0:10, 1:20, 2: 30}))
‘’’
0 1 2
0 1.0 2.0 3.0
1 10.0 5.0 30.0
2 10.0 9.0 8.0
3 10.0 20.0 30.0
‘’’
向上填充
print(df1.fillna(method=’ffill’))
‘’’
0 1 2
0 1.0 2.0 3.0
1 1.0 5.0 3.0
2 1.0 9.0 8.0
3 1.0 9.0 8.0
‘’’
去重
s1 = pd.Series(list(‘aaaabbbbccccde’))
print(s1)
‘’’
0 a
1 a
2 a
3 a
4 b
5 b
6 b
7 b
8 c
9 c
10 c
11 c
12 d
13 e
dtype: object
‘’’
s2 = pd.DataFrame({
‘A’: [1, 1, 1, 2, 2, 3, 4, 1],
‘B’: list(‘aaabbbcU’)
})
print(s2)
‘’’
dtype: object
A B
0 1 a
1 1 a
2 1 a
3 2 b
4 2 b
5 3 b
6 4 c
7 1 U
‘’’
drop_duplicates() 去重
print(s1.drop_duplicates())
‘’’
0 a
4 b
8 c
12 d
13 e
dtype: object
‘’’
print(s2.drop_duplicates())
‘’’
A B
0 1 a
3 2 b
5 3 b
6 4 c
7 1 U
‘’’
指定对某一列进行去重（A 列）
print(s2.drop_duplicates([‘A’]))
‘’’
A B
0 1 a
3 2 b
5 3 b
6 4 c
‘’’
统计重复值出现的次数
print(s1.value_counts())
‘’’
a 4
b 4
c 4
d 1
e 1
Name: count, dtype: int64
‘’’
unique() 得到唯一值；
替换：replace()
前面是旧值，后面是新值
s = pd.Series(list(‘aaabbbcde’))
print(s)
‘’’
0 a
1 a
2 a
3 b
4 b
5 b
6 c
7 d
8 e
dtype: object
‘’’
将里面的 c 替换成空值
print(s.replace(‘c’, np.NaN))
‘’’
0 a
1 a
2 a
3 b
4 b
5 b
6 NaN
7 d
8 e
dtype: object
‘’’
批量指定替换
print(s.replace({‘a’: ‘Python’, ‘b’: ‘Golang’}))
‘’’
0 Python
1 Python
2 Python
3 Golang
4 Golang
5 Golang
6 c
7 d
8 e
dtype: object
‘’’
str 属性
df = pd.DataFrame({
‘k1’: list(‘abcdef’),
‘k2’:[‘h’, ‘haha’, ‘six’, ‘star’, np.nan, ‘123’]
})
print(df)
‘’’
k1 k2
0 a h
1 b haha
2 c six
3 d star
4 e NaN
5 f 123
‘’’
count() 统计元素出现的次数
s = pd.Series(list(‘aaabbbcde’))
统计 a 出现的次数
print(s.str.count(‘a’))
‘’’
0 1
1 1
2 1
3 0
4 0
5 0
6 0
7 0
8 0
dtype: int64
‘’’
lower() 将字符串中的大字母变换成小写
upper() 将字符串中的小写字母替换成大写
把 k1 列变成大写
print(df[‘k1’].str.upper())
‘’’
dtype: int64
0 A
1 B
2 C
3 D
4 E
5 F
‘’’
df[‘k3’] = df[‘k1’].str.upper()
print(df)
‘’’
k1 k2 k3
0 a h A
1 b haha B
2 c six C
3 d star D
4 e NaN E
5 f 123 F
‘’’
len() 求长度
startswith() 表示以什么开头
endswith() 表示以什么结尾
replace() 替换
df = pd.DataFrame(np.random.randn(3, 2), columns=[‘ col A’, ‘col B’], index=range(3))
print(df)
‘’’
注意： col A 前面是有空格的
col A col B
0 -0.328012 1.339511
1 -1.614227 -1.658222
2 -1.599471 -1.161017
‘’’
df.columns = df.columns.str.replace(‘ ‘, ‘-‘)
print(df)
‘’’
-col-A col-B
0 -0.328012 1.339511
1 -1.614227 -1.658222
2 -1.599471 -1.161017
‘’’
split() 分割,
要处理的数据必须是字符串个是
s = pd.Series([‘a, b, c’, ‘1, 2, 3’, np.nan, [‘a, a, a’]])
print(s)
‘’’
0 a, b, c
1 1, 2, 3
2 NaN
3 [a, a, a]
dtype: object
‘’’
按逗号分割
print(s.str.split(‘,’))
‘’’
0 [a, b, c]
1 [1, 2, 3]
2 NaN
3 NaN
dtype: object
‘’’
取整个分割的第一个单元格
注意：这种方式取值会视整个数据为一个嵌套列表，即类似于 [[a, b, c], [1, 2, 3], [NaN], [Nan]]，而[0] 表示取索引为 0 行对应的数据
print(s.str.split(‘,’)[0])
‘’’
[‘a’, ‘ b’, ‘ c’]
‘’’
str 定位到单元格内，取单元格内的第一个元素
注意：下面这种方式取值是定位每个子列表中的索引进行取值
print(s.str.split(‘,’).str[0])
‘’’
0 a
1 1
2 NaN
3 NaN
dtype: object
‘’’
拆分
print(s.str.split(‘,’, expand=True))
‘’’
0 1 2
0 a b c
1 1 2 3
2 NaN NaN NaN
3 NaN NaN NaN
‘’’
extract() 提取
通过正则表达方式提取内容
data = {
‘info’: [‘Jone 24’, ‘Lucy 30’, ‘Bob 28’]
}
df = pd.DataFrame(data)
df[‘name’] = df[‘info’].str.extract(r’(\w+)’)
print(df)
df[‘age’] = df[‘info’].str.extract(r’(\d+)’)
print(df)
df = pd.DataFrame({
‘k1’: [‘a, b, c’, ‘1, 2, 3’, [‘a, ., ‘]],
‘k2’: [‘a-b-c’, ‘1-2-3’, [‘-,:- ‘]]
})
字符串索引 通过下标取值
str 属性生活案例
data = {
‘姓名’: [‘lily Smith’, ‘lucy Johnson’, ‘jack Brown’, ‘tom Lee’],
‘入职日期’: [‘2022-05-15’, ‘2020-10-01’, ‘2019-07-20’, ‘2023-03-10’]
}
df = pd.DataFrame(data)
print(df)
‘’’
姓名 入职日期
0 lily Smith 2022-05-15
1 lucy Johnson 2020-10-01
2 jack Brown 2019-07-20
3 tom Lee 2023-03-10
‘’’
需求：将名首字母大写
df[‘名’] = df[‘姓名’].str.split(‘ ‘).str[0].str.capitalize()
print(df)
‘’’
姓名 入职日期 名
0 lily Smith 2022-05-15 Lily
1 lucy Johnson 2020-10-01 Lucy
2 jack Brown 2019-07-20 Jack
3 tom Lee 2023-03-10 Tom
‘’’
分组聚合
df = pd.DataFrame({
‘name’: [‘BOSS’, ‘Lilei’, ‘Lilei’, ‘Han’, ‘BOSS’, ‘BOSS’, ‘Han’, ‘BOSS’],
‘Year’: [2020, 2020, 2020, 2020, 2021, 2021, 2021, 2021],
‘salary’: [999999, 20000, 25000, 5000, 9999999, 999999, 7500, 999999],
‘Bouns’: [100000, 20000, 20000, 5000, 200000, 300000, 3000, 400000]
})
print(df)
‘’’
name Year salary Bouns
0 BOSS 2020 999999 100000
1 Lilei 2020 20000 20000
2 Lilei 2020 25000 20000
3 Han 2020 5000 5000
4 BOSS 2021 9999999 200000
5 BOSS 2021 999999 300000
6 Han 2021 7500 3000
7 BOSS 2021 999999 400000
‘’’
print(df.groupby(‘name’).count())
‘’’
Year salary Bouns
name
BOSS 4 4 4
Han 2 2 2
Lilei 2 2 2
‘’’
print(df.groupby(‘name’).mean())
‘’’
Year salary Bouns
name
BOSS 2020.75 3249999.0 250000.0
Han 2020.50 6250.0 4000.0
Lilei 2020.00 22500.0 20000.0
‘’’
data = {
‘Category’: [‘A’, ‘A’, ‘B’, ‘B’, ‘A’, ‘B’],
‘Value’: [1, 2, 3, 4, 5, 6]
}
df = pd.DataFrame(data)
print(df)
‘’’
Category Value
0 A 1
1 A 2
2 B 3
3 B 4
4 A 5
5 B 6
‘’’
print(df.groupby(‘Category’).agg({‘Value’: [‘sum’, ‘mean’, ‘max’]}))
‘’’
sum mean max
Category
A 8 2.666667 5
B 13 4.333333 6
‘’’
